timberlake chemistry practice test ch 7
atm} \times 2.0\,\text{L}}{300\,\text{K}} = \frac{P_2 \times 1.0\,\text{L}}{600\,\text{K}} \] \[ P_2 = \frac{1\,\text{atm} \times 2.0\,\text{L} \times 600\,\text{K}}{300\,\text{K} \times 1.0\,\text{L}} = 4\,\text{atm} \] 4. Solutions
